10 SQL Assessment Interview Questions and Answers
Prepare for your next interview with our comprehensive guide to SQL assessment questions, designed to enhance your database management skills.
Prepare for your next interview with our comprehensive guide to SQL assessment questions, designed to enhance your database management skills.
SQL remains a cornerstone of database management and manipulation, essential for handling structured data in various applications. Its ability to efficiently query, update, and manage data makes it indispensable for roles in data analysis, software development, and database administration. SQL’s widespread adoption across industries underscores its importance as a fundamental skill for technical professionals.
This article offers a curated selection of SQL questions designed to test and enhance your understanding of key concepts and practical applications. By working through these questions, you will be better prepared to demonstrate your SQL proficiency and problem-solving abilities in an interview setting.
Database normalization involves structuring a relational database to reduce redundancy and improve data integrity. It typically involves dividing a database into multiple tables and defining relationships between them. The process is done in stages, known as “normal forms,” with the most common being:
Normalization is important for maintaining data consistency, efficient data management, optimized queries, and reducing anomalies.
An index in SQL is a database object that enhances data retrieval speed on a table at the cost of additional storage. Indexes are created on columns frequently used in WHERE clauses, JOIN conditions, or ORDER BY clauses. By creating an index, the database can quickly locate data without a full table scan.
Types of indexes include:
Example:
CREATE INDEX idx_last_name ON employees(last_name); SELECT * FROM employees WHERE last_name = 'Smith';
Creating an index on the ‘last_name’ column allows the database to quickly locate rows where the last name is ‘Smith’, improving query performance.
A subquery in SQL is a query nested inside another query, used for operations requiring multiple steps. For example, to find employees earning more than the average salary:
SELECT employee_id, employee_name, salary FROM Employees WHERE salary > (SELECT AVG(salary) FROM Employees);
The subquery calculates the average salary, and the outer query selects employees with salaries above this average.
ACID properties ensure the integrity and reliability of database transactions:
Window functions perform calculations across a set of table rows related to the current row. For example, to rank employees by salary within each department:
SELECT employee_id, department_id, salary, RANK() OVER (PARTITION BY department_id ORDER BY salary DESC) AS salary_rank FROM employees;
The RANK() function assigns a rank based on salary within each department, using PARTITION BY to divide the result set.
Stored procedures are precompiled collections of SQL statements stored under a name and processed as a unit. They can accept input parameters, return output parameters, and provide multiple result sets.
Advantages:
Securing a SQL database involves several practices:
To retrieve the top 10 highest-paid employees from a large “Employees” table:
SELECT employee_id, employee_name, salary FROM Employees ORDER BY salary DESC LIMIT 10;
Common Table Expressions (CTEs) simplify complex queries by breaking them into manageable parts. Defined using the WITH keyword, they can be referenced multiple times within the main query.
Example:
WITH Sales_CTE AS ( SELECT SalesPersonID, SUM(SalesAmount) AS TotalSales FROM Sales GROUP BY SalesPersonID ) SELECT SalesPersonID, TotalSales FROM Sales_CTE WHERE TotalSales > 10000;
The CTE Sales_CTE calculates total sales for each salesperson, and the main query selects those with total sales over 10,000.
In SQL, NULL values represent missing or unknown data. Handling NULL values is important for accurate data retrieval. Common methods include:
Examples:
SELECT * FROM employees WHERE manager_id IS NULL; SELECT * FROM employees WHERE manager_id IS NOT NULL; SELECT employee_id, COALESCE(manager_id, 'No Manager') AS manager_id FROM employees; SELECT employee_id, NULLIF(manager_id, 0) AS manager_id FROM employees;